Question

Resolva:
(x+1)(x+2)-2(x-3)=10

Answer 1

Resposta:

(x+1)(x+2)-2(x-3)=10

${x}^{2} + 2x + x + 2 - 2x - 6 = 10 \\ {x}^{2} + x - 4 = 10 \\ {x}^{2} + x - 4 - 10 = 0 \\ {x}^{2} + x - 14 = 0 \\ x = \frac{ - 1 \frac{ + }{ - } \sqrt{ {1}^{2} - 4 \times 1 \times ( - 14)} }{2 \times 1} \\ x = \frac{ - 1 \frac{ + }{ - } \sqrt{1 + 56} }{2} \\ x = \frac{ - 1 \frac{ + }{ - } \sqrt{57} }{2} \\ x = \frac{ - 1 + \sqrt{57} }{ 2} \\ x = \frac{ - 1 - \sqrt{57} }{2}$