Question

resolva utilizando a formula de bhaskara

Answer 1

Bom Dia !!!

$2x^{2} - 4x + 3\\\\a = 2\\\\b = -4\\\\c = 3\\\\\Delta = b^2-4.a.c\\\\\Delta = (-4)^2-4.2.3\\\\\Delta = 8 - 24\\\\\Delta = 16\\\\Nesse\ caso\ a\ equa\c{c}~{a}o\ ser\'a\ inexistente,\ pois\\n\~{a}o\ existe\ conjunto\ de\ n\'umeros\ negativos.\\\\\Delta = \in$

Espero ter ajudado :-)

Att: LDC

Answer 2

Resposta:

2x² -- 4x + 3 = 0

4x -- 4x = 0x = x

x + 3 = 3x

3x / 3 = 0

resultado: 0

Explicação passo-a-passo: