Question

Resolva usando as propriedades das potências, deixando de forma simplificada.

Answer 1

$b)(2^3)^4.2= 2^1^2.2=2^1^3 \\ \\ c)(3^2)^2.(3^-^4)^-^2=3^4.3^8=3^1^2 \\ \\ d)(5^3)^2.25.125=5^6.5^2.5^3=5^1^1 \\ \\ e)256.32.16=2^8.2^5.2^4=2^1^7 \\ \\ f)1000.10^2.10^-^4=10^3.10^2.10^-^4=10^5.10^-^4=10^1=10 \\ \\ g)3^1.3^-^8.3^2^1=3^1^4 \\ \\ h) (5^4^3:5^4^0).5^-^3=5^3.5^-^3=5^0=1 \\ \\ i) (11^2:11^-^4)=11^-^2= \frac{1}{11^2} = \frac{1}{121}$


basta aplicar as propriedades da potencia..bons estudos