Question

Resolva por meio da fatoração ou Bhaskara: 4z²-12z+9=0

Answer 1

4z²-12z+9=0
(2z-3)² = 0
|2z-3|=0

2z - 3 = 0 ---> z = 3/2

Answer 2

$4z^2-12z+9=0 \\ \\ \Delta = (-12)^2 - 4.4.9 \\ \Delta = 0 \to \ (raizes \ iguais)$

$z = \frac{-(-12) \pm \sqrt{0} }{2.4} = \frac{12 \pm 0}{8} \\ \\ z' = \frac{12}{8} =\boxed{ \frac{3}{2}} \\ \\ z'' = \frac{12}{8} = \boxed{ \frac{3}{2}}$