Question

Resolva por bhaskara

n2-3n-40=0

Answer 1

Resposta:

Explicação passo-a-passo:

$\displaystyle Aplicando~a~f\'{o}rmula~de~Bhaskara~para~n^{2}-3n-40=0~~\\e~comparando~com~(a)n^{2}+(b)n+(c)=0,~temos~a=1{;}~b=-3~e~c=-40\\\\\Delta=(b)^{2}-4(a)(c)=(-3)^{2}-4(1)(-40)=9-(-160)=169\\\\n^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(-3)-\sqrt{169}}{2(1)}=\frac{3-13}{2}=\frac{-10}{2}=-5\\\\n^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(-3)+\sqrt{169}}{2(1)}=\frac{3+13}{2}=\frac{16}{2}=8\\\\S=\{-5,~8\}$