Matemática, perguntado por jpnovaes360, 6 meses atrás

resolva pelo método da adição
1) {x+y=85
{x-y=65

2) {x+y=72
{x-y=30

Soluções para a tarefa

Respondido por arielsilva1512
1

Resposta:

1) {x+y=85

{x-y=65

\left \{ {{x+y=85} \atop {x-y=65} \right. \\\\2x = 150\\\\x=\frac{150}{2} \\\\x=75\\x+y=85\\75+y=85\\y=85-75\\y=10\\(x,y) = (75,10)

2) {x+y=72

{x-y=30

\left \{ {{x+y=72} \atop {x-y=30}} \right.\\\\2x=102\\\x=\frac{102}{2} \\\\x=51\\\\x+y=72\\51+y=72\\y=72-51\\y=21\\\\(x,y) = (51,21)

Respondido por ewerton197775p7gwlb
1

 > resolucao \\  \\  \geqslant sistema \: de \: equacao \\  \\ x + y = 85 \\ x - y = 65 \\  \\ 2x = 150 \\ x =  \frac{150}{2}  \\ x = 75 \\  \\ y = 85 - x \\ y = 85 - 75 \\ y = 10 \\  \\  \\  =  =  =  =  =  =  =  =  =  =  =  =  =  =  =  =  =  \\  \\  \\ x + y = 72 \\ x - y = 30 \\  \\ 2x = 102 \\ x =  \frac{102}{2}  \\ x = 51 \\  \\ y = 72 - x \\ y = 72 - 51 \\ y = 21 \\  \\  \\  \\  \geqslant  \geqslant  \leqslant  \geqslant  \leqslant  \geqslant  \leqslant  \geqslant  \leqslant  \geqslant  \geqslant

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