Question

Resolva pela forma de bhaskara
a) 2x²-19x-10=0

Answer 1

2x² - 19x - 10 = 0
a = 2; b = - 19; c = - 10

Δ = b² - 4ac
Δ = (-19)² - 4.2.(-10)
Δ = 361 - 8.(-10)
Δ = 361 + 80
Δ = 441

x = - b +/- √Δ  = - ( - 19) +/-√441
        2a                     2.2

x = 19 + 21 = 40/4 = 10
          4

x = 19 - 21 = - 2/4 = - 1/2
          4

R.: x = 10 e x = - 1/2

Answer 2

2x^2-19x-10=0

∆=√361-8.(-10)

∆=√361+80

∆=√441

x1=19+21/4

x1=40/4

x1=10

x2=19-21/4

x2=-2/4

x2=-1/2