Question

resolva para mim
x²+8x-4=0

Answer 1

x²+8x-4=0
a=1
b=8
c=-4

Δ=b²-4ac
Δ=8²-4(-4)
Δ=64+16
Δ=80
√Δ=√80
√80=±√2².2².5=±4√5

$x= \frac{-b\pm \sqrt{delta} }{2a} = \frac{-8\pm4 \sqrt{5} }{2} = \frac{2(-4\pm2 \sqrt{5}) }{2} =-4\pm2 \sqrt{5}$

$x'=-4+2 \sqrt{5} \\ \\ x"=-4-2 \sqrt{5}$

Answer 2

x

′

=−4+2

5

x"=−4−2

5

blz valeu