Question

Resolva os sistemas seguir pelo método da adição x+y=4 e x-y=2​

Answer 1

Resposta:

x + Y = 4

x - Y = 2

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2x + 0y = 8

2x = 8

x = 8/2

x = 4

Answer 2

Resposta:

OLÁ VAMOS A SUA PERGUNTA:⇒⇒

$\left. \begin{cases} { x+y=4 } \\ { x-y=2 } \end{cases} \right.$

$x+y=4,x-y=2$

$\left(\begin{matrix}1&1\\1&-1\end{matrix}\right)\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}4\\2\end{matrix}\right)$

$inverse(\left(\begin{matrix}1&1\\1&-1\end{matrix}\right))\left(\begin{matrix}1&1\\1&-1\end{matrix}\right)\left(\begin{matrix}x\\y\end{matrix}\right)=inverse(\left(\begin{matrix}1&1\\1&-1\end{matrix}\right))\left(\begin{matrix}4\\2\end{matrix}\right)$

$\left(\begin{matrix}1&0\\0&1\end{matrix}\right)\left(\begin{matrix}x\\y\end{matrix}\right)=inverse(\left(\begin{matrix}1&1\\1&-1\end{matrix}\right))\left(\begin{matrix}4\\2\end{matrix}\right)$

$\left(\begin{matrix}x\\y\end{matrix}\right)=inverse(\left(\begin{matrix}1&1\\1&-1\end{matrix}\right))\left(\begin{matrix}4\\2\end{matrix}\right)$

$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}\frac{-1}{-1-1}&-\frac{1}{-1-1}\\-\frac{1}{-1-1}&\frac{1}{-1-1}\end{matrix}\right)\left(\begin{matrix}4\\2\end{matrix}\right)$

$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}\frac{1}{2}&\frac{1}{2}\\\frac{1}{2}&-\frac{1}{2}\end{matrix}\right)\left(\begin{matrix}4\\2\end{matrix}\right)$

$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}\frac{1}{2}\times 4+\frac{1}{2}\times 2\\\frac{1}{2}\times 4-\frac{1}{2}\times 2\end{matrix}\right)$

$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}3\\1\end{matrix}\right)$

$\star \: \text{Extraia os elementos x e y da matriz.}$

$\color{green}{}\boxed{\bold{\displaystyle{\clubsuit\ \spadesuit\ \maltese  x=3,y=1 }}}\ \checkmark</p><p></p><p>$

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