Question

resolva os sistemas se possível classifique-os x+y+2z=4

2x-3y+z=0

5x-y-z=3

Answer 1

Resposta:

x+y+2z= 4

2x-3y+z=0

5x-y-z=3

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x+y+2z= 4 x(-2)

2x-3y+z= 0

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-2x-2y-4z=-8

2x-3y+z=0

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-5y -3z=-8

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2x-3y+z= 0 x(5)

5x-x-z= 3. x(-2)

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10x-15y+5z=0

-10x +2y+2z= -6

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-13y +7z= -6 x(-5)

- 5y-3z= -8. x(13)

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65y-35y= 30

-65y-39y= -104

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-74z= -74

z= -74/-74

z= 1

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-5y-3z=-8

-5y-3*1=-8

-5y-3= -8

-5y= -8+3

-5y= -5

y= -5/-5= 1

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x+y+2z= 4

1+1+2z= 4

2+2z=4

2z=4-2

z= 2/2

z= 1

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S={(1,1,1)}