Question

resolva os sistemas pela regra de cramer

a)2x+y+z=0
-x+2y+2z=3
-2x+3y+5z=7

b) 4x+3y+z=6
3x-8y+z=-3
x+y+2z=9

Answer 1

Oi Gean

a)

2x + y + z = 0
-x + 2y + 2z = 3
-2x + 3y + 5z = 7

detA = 10
detAx = -6
detAy = 1
detAz = 11

x = detAx/detA = -6/10
y = detAy/detA = 1/10
z = detAz/detA = 11/10 

b) 

4x + 3y + z = 6
3x -8y + z = -3
x + y + 2z = 9

detA = -72
detAx = 12
detAy = -60
detAz = -300

x = detAx/detA = -12/72 = -1/6
y = detAy/detA = -60/-72 = 5/6
z = detAz/detA = -300/-72 = 25/6 

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