Question

resolva os sistemas abaixo usando a regra de cramer 3×+2y=7
2×+3y=8​

Answer 1

$| {(3x + 2y = 7)}^{ - 2} \\| {(2x + 3y = 8)}^{3}\\ \\ | 6x - 4y = - 14 \\ |6x + 9y = 24 \\ \\ 5y = 10 \\ y = \frac{10}{5} \\ y = 2 \\ \\ \\ 2x + 3y = 8 \\ 2x + 3 \times 2 = 8 \\ 2x + 6 = 8\\ 2x = 8 - 6 \\ 2x = 2 \\ x = \frac{2}{2} \\ x = 1$