Question

resolva os seguintes sistemas lineares {-x-4y=0 {3x+2y=5

Answer 1

{-x -4y = 0
{3x +2y = 5 *(2)

{-x -4y = 0
{6x +4y = 10
5x ± 0y = 10
x = 10/5
x = 2

{-x -4y = 0
-2 -4y = 0
4y = -2
y = -0,5.

Answer 2

-x-4y=0 -> x= -4y    -> x= -4(-1/2)   x=4/2  x=2
3x+2y=5

3(-4y)+2y=5
-12y+2y=5
-10y=5
y= -5/10
y= -1/2