Question

Resolva os seguintes produtos notáveis.

Quadrado da diferença de dois termos:

a) ( a - b ) ² =

b) ( 2x - y ) ² =

c) ( y - 10 ) ² =

d) ( 2y - 4 ) ² =

e) ( 3x - 3 ) ² =

f) ( 5x - 2y ) ² =

g) ( a - 1 ) ² =

h) ( 10x - 5 ) ² =

i) ( x - 1 ) ² =

j) ( 20x - 2y ) ² =​

Answer 1

Resposta:

acho q e isso espero ter ajudado

Answer 2

Oie, Td Bom?!

a)

$= (a - b) {}^{2}$

$= a {}^{2} - 2ab + b {}^{2}$

b)

$= (2x - y) {}^{2}$

$= (2x) {}^{2} - 2 \: . \: 2xy + y {}^{2}$

$= 4x {}^{2} - 4xy + y {}^{2}$

c)

$= (y - 10) {}^{2}$

$= y {}^{2} - 2y \: . \: 10 + 10 {}^{2}$

$= y {}^{2} - 20y + 100$

d)

$= (2y - 4) {}^{2}$

$= (2y) {}^{2} - 2 \: . \: 2y \: . \: 4 + 4 {}^{2}$

$= 4y {}^{2} - 16y + 16$

e)

$= (3x - 3) {}^{2}$

$= (3x) {}^{2} - 2 \: . \: 3x \: . \: 3 + 3 {}^{2}$

$= 9x {}^{2} - 18x + 9$

f)

$= (5x - 2y) {}^{2}$

$= (5x) {}^{2} - 2 \: . \: 5x \: . \: 2y + (2y) {}^{2}$

$= 25x {}^{2} - 20xy + 4y {}^{2}$

g)

$= (a - 1) {}^{2}$

$= a {}^{2} - 2a \: . \: 1 + 1 {}^{2}$

$= a {}^{2} - 2a + 1$

h)

$= (10x - 5) {}^{2}$

$= (10x) {}^{2} - 2 \: . \: 10x \: . \: 5 + 5 {}^{2}$

$= 100x {}^{2} - 100x + 25$

i)

$= (x - 1) {}^{2}$

$= x {}^{2} - 2x \: . \: 1 + 1 {}^{2}$

$= x {}^{2} - 2x + 1$

j)

$= (20x - 2y) {}^{2}$

$= (20x) {}^{2} - 2 \: . \: 20x \: . \: 2y + (2y) {}^{2}$

$= 400x {}^{2} - 80xy + 4y {}^{2}$

Att. Makaveli1996