Question

resolva os polinomios:
Pra agr pfv!!

Answer 1

$10 x^{2} -8x-9= 0$  Resolver por Bhaskara

Achar delta:

Δ= $\sqrt{- 8^{2} -4*10*(-9)}$

Δ= $\sqrt{64+360} = \sqrt{424} = \sqrt{ 2^{3} *53} =2 \sqrt{106}$

$x'= \frac{8+2 \sqrt{106} }{2*10} = \frac{8+2 \sqrt{106} }{20} \\ \\ x"= \frac{8-2 \sqrt{106} }{2*10} = \frac{8-2 \sqrt{106} }{20}$