Question

Resolva o sistema x+y+z=6 x+z=2 z=1

Answer 1

$\large Os ~valor ~de~~ x, y,~ e~ z$

$\large x= 1 \\\\\large y = 4 \\\\\large z=1$

                                  $\LargeSistema ~de ~equac_{\!\!,}\tilde oes$

$\Large\begin{cases} x+y+z=6~~ ( I ) \\x+z=2~~( I )\\z=1 ~~( III) \end{cases}$

Como z  = 1, substituir em ( II )

$\Large x+z=2 \\\\\Large x+1=2 \\\\\Large x = 2 - 1 \\\\\Large x= 1$

Como z = 1  e x = 1, substituir os valores em ( I ).

$\Largex+y+z=6 \\\\\Large1+y+1=6 \\\\\Largey + 2=6 \\\\\Largey = 6 - 2 \\\\ \Largey = 4$

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