Question

resolva o sistema linear
{x+y+z=8
{x-y=0
{3y+2z=14​

Answer 1

x = y

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$\left \{ {{x+y+z=8} \atop {3y+2z=14}} \right. \\\\\left \{ {{2y+z=8} \atop {3y+2z=14}} \right.$

z = 8 - 2y

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3y + 2(8 - 2y) = 14

3y + 16 - 4y = 14

-y = -2

y = 2

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x = y

x = 2

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2 + 2 + z = 8

z = 4