Question

resolva o sistema a seguir usando a regra de Cramer:
a)
X - 2y +3z =0
-2x + 5y - 3z =1
-x +3y - 2z =5

b)
-2x + 4y - 2z =2
3x - 5y + z = -7
2x - 5z = -16

me ajudem por favor ​

Answer 1

Vamos là.

A)

x - 2y +3z = 0

-2x + 5y - 3z = 1

-x +3y - 2z = 5

determinantes

D = -2

Dx = -20

Dy = -14

Dz = 4

x = Dx/D = -20/-2 = 10

y = Dy/D = -14/-2 = 7

z = Dz/D = 4/-2 = -2

S = (10, 7, -2)

B)

-2x + 4y - 2z =2

3x - 5y + z = -7

2x - 5z = -16

determinantes

D = -2

Dx = 6

Dy = 0

Dz = -4

x = Dx/D = 6/-2 = -3

y = Dy/D = 0/-2 = 0

z = Dz/D = -4/-2 = 2

S = (-3, 0, 2)