Question

Resolva o seguinte cálculo:

$\begin{gathered} \int \frac{1}{x {}^{2} \sqrt{x {}^{2} + 4 } } \cdot \: dx \\\end{gathered}$​

Answer 1

• resposta será:

$\large\displaystyle\text{ \begin{aligned}\therefore \boxed{\boxed{\pink{\int \frac{1}{x^2 \sqrt{x^2 + 2^2}} dx = \frac{-\sqrt{x^2+4}}{4x} + k, k\in \mathbb{R}}}}\end{aligned} }$