Question

) Resolva o quadrado da soma de dois termos.
a) (x + 5)²
b) (2x + 4)²
c) (y + 6)²
d) (4x + 5)²
e) (3x +3)²

Answer 1

$\Large\boxed{\boxed{\boxed{{Ola\´\ }}}}}$

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a)

$\sf {(x + 5)}^{2} \\ \\ \sf {x}^{2} + 2x.5 + {5}^{2} \\ \sf {x}^{2} + 10x + {5}^{2} \\ \sf \large\boxed{{\sf \blue{x}^{ \blue2} \blue+ \blue1 \blue0 \blue x \blue + \blue2 \blue5{}}}$

b)

$\sf {(2x + 4)}^{2} \\ \\ \sf{(2x)}^{2} + 2.2x.4 + {4}^{2} \\ \sf{4x}^{2} + 2.2x.4 + {4}^{2} \\ \sf{4x}^{2} +16x + {4}^{2} \\\large\boxed{{\sf \sf \blue{4x}^{ \blue2} \blue+ \blue1 \blue6 \blue x \blue+ \blue1 \blue6{}}}$

c)

$\sf {(y + 6)}^{2} \\ \\ \sf {y}^{2} + 2y.6 + {6}^{2} \\ \sf {y}^{2} + 12y + {6}^{2} \\ \large\boxed{{\sf \sf \blue{y}^{ \blue2} \blue+ \blue1 \blue2 \blue y \blue+ \blue3 \blue6{}}}$

d)

$\sf {(4x + 5)}^{2} \\ \\ \sf{(4x)}^{2} + 2.4x.5 + {5}^{2} \\ \sf {16x}^{2} + 2.4x.5 + {5}^{2} \\ \sf{16x}^{2} + 40x + {5}^{2} \\\large\boxed{{\sf \sf \blue{16x}^{ \blue2} \blue+ \blue4 \blue0 \blue x \blue+ \blue2 \blue5 {}}}$

e)

$\sf {(3x + 3)}^{2} \\ \\ \sf {(3x)}^{2} + 2.3x.3 + {3}^{2} \\ \sf {9x}^{2} + 2.3x.3 + {3}^{2} \\ \sf {9x}^{2} + 18x + {3}^{2} \\\large\boxed{{\sf \blue{9x}^{ \blue2} \blue+ \blue1 \blue8 \blue x \blue+ \blue9 {}}}$