Question

Resolva nos reais, a seguinte equação:

$x^{4} - 20x^{2} - 576 = 0$

Answer 1

x^4-20x^2-576=0
y^2-20y-576=0
delta=b^2-4ac
delta=(-20)^2-4.1.(-576)
delta=400+2304
delta=2704
x=-b-/+ raiz de delta/2a
x=-(-20)-52/2.1
x=20-52/2
x=-32/2
x=-16
x=-(-20)+52/2.1
x=20+52/2
x=72/2
x=36
S={-16, +16, +36, -36}