Question

resolva no conjunto R, as seguintes?

x² - 2x = 2X - 4​

Answer 1

Resposta:

Explicação passo a passo:

x² - 2x = 2x - 4​

x² - 4x + 4​=0

$\displaystyle Aplicando~a~f\acute{o}rmula~de~Bhaskara~para~x^{2}-4x+4=0~~e~comparando~com~(a)x^{2}+(b)x+(c)=0,~determinamos~os~coeficientes:~\\a=1{;}~b=-4~e~c=4\\\\C\acute{a}lculo~do~discriminante~(\Delta):&\\&~\Delta=(b)^{2}-4(a)(c)=(-4)^{2}-4(1)(4)=16-(16)=0\\\\C\acute{a}lculo~das~raizes:&\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(-4)-\sqrt{0}}{2(1)}=\frac{4-0}{2}=\frac{4}{2}=2\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(-4)+\sqrt{0}}{2(1)}=\frac{4+0}{2}=\frac{4}{2}=2\\\\S=\{2,~2\}$

Answer 2

Explicação passo-a-passo:

x² - 2x = 2x - 4

x² - 2x - 2x + 4 = 0

x² - 4x + 4 = 0

(x - 2)² = 0

x - 2 = 0

x = 2

Sol: { 2 } ✓✓✓