Question

resolva,no conjunto R, as seguintes equações

c)
$6x {}^{2} + 3x + 1 = 4x {}^{2}$
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Answer 1

Resposta:

Explicação passo a passo:

6x²+3x+1=4x²

6x²+3x+1-4x²=0

2x²+3x+1=0

$\displaystyle Aplicando~a~f\acute{o}rmula~de~Bhaskara~para~2x^{2}+3x+1=0~~e~comparando~com~(a)x^{2}+(b)x+(c)=0,~determinamos~os~coeficientes:~\\a=2{;}~b=3~e~c=1\\C\acute{a}lculo~do~discriminante~(\Delta):&\\&~\Delta=(b)^{2}-4(a)(c)=(3)^{2}-4(2)(1)=9-(8)=1\\C\acute{a}lculo~das~raizes:&\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(3)-\sqrt{1}}{2(2)}=\frac{-3-1}{4}=\frac{-4}{4}=-1\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(3)+\sqrt{1}}{2(2)}=\frac{-3+1}{4}=\frac{-2}{4}=-\frac{1}{2}$