Question

resolva na fórmula de Bhaskara:
x²-6x-27=0​

Answer 1

Explicação passo-a-passo:

∆= (-6)² - 4.1.(-27)

∆= 36 + 108

∆= 144

x= - (-6) ±√144/2.1

x= 6 ± 12/2

x1= 6+12/2= 18/2= 9

x2= 6-12/2= - 6/2= -3

S = { - 3, 9 }

Answer 2

$\large\displaystyle\rm x^2-6x-27=0$

$\large\displaystyle\rm \Delta=b^2-4\cdot a\cdot c$

$\large\displaystyle\rm \Delta= (-6)^2-4\cdot1\cdot(-27)$

$\large\displaystyle\rm\Delta=36+108$

$\large\displaystyle\rm\Delta=144$

$\large\displaystyle\text{ \rm x=\dfrac{-b\pm\sqrt{\Delta}}{2\cdot a} }$

$\large\displaystyle\text{ \rm x=\dfrac{-(-6)\pm\sqrt{144}}{2\cdot1} }$

$\large\displaystyle\rm x=\dfrac{6\pm12}{2}\begin{cases}\rm x_1=\dfrac{6+12}{2}=\dfrac{18}{2}=9\\\\\rm x_2=\dfrac{6-12}{2}=\dfrac{-6}{2}=-3\end{cases}$

$\large\displaystyle\text{ \boxed{\boxed{\rm S=\{-3;9\}}} }$