Question

resolva na fórmula de Bhaskara x²+5x-24=0​

Answer 1

Resposta:

Explicação passo a passo:

$x^2+5x-24=0​\\Delta= b^2-4.a.c= 5^2-4.1.(-24) = 25+96 = 121\\x^'=\frac{ -b+\sqrt{delta}}{2.a}= \frac{ -5+\sqrt{121}}{2.1}= \frac{-5+11}{2} = \frac{6}{2} = 3$

$x^''= \frac{-b-\sqrt{delta} }{2.a} = \frac{-5-\sqrt{121} }{2.1} = \frac{-5-11\ }{2} = \frac{-16 }{2} = -8$