Question

resolva

log x na base 2 - log (3x - 5) na base 2= 1

Answer 1

$lo g_{2} x-lo g_{2}(3x-5)=1 \\ \\ lo g_{2} \frac{x}{(3x-5)} =lo g_{2}2 \\ \\ \frac{x}{(3x-5)}=2 \\ \\ x=2(3x-5) \\ \\ x=6x-10 \\ \\ -5x=-10 \\ \\ 5x=10 \\ \\ x=\frac{10}{5}\\ \\ x=2$