Question

resolva: log(x+6) de base 2 - logx de base 2=log4 de base 2

Answer 1

vamos lá...

usar o propriedade :

$logx-logy=logx/y \\ \\ \log_2(x+6)-\log_2x=\log_24 \\ \\ \log_2 \frac{x+6}{x} =\log_2=4 \\ \\ \frac{x+6}{x} =4 \\ \\ 4x=x+6 \\ \\ 4x-x=6 \\ \\ 3x=6 \\ \\ x=6\div3 \\ \\ x=2$

Answer 2

log₂(x+6)  - log₂x =log₂4 

log₂(x+6)/x=log₂4

(x+6)/x=4

x+6=4x

3x=6

x=2