resolva: log x 16= -2
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![log_{x}16=-2\\\\\\
(x)^{-2}=16\\\\\
(\frac{1}{ x^{2} })=16\\\\\
16 x^{2} =1\\\\\
x^{2} = \frac{1}{16} \\\\\\
x= \sqrt{ \frac{1}{16} } \\\\\\
x= \frac{1}{4}\\\\\\\\\
\boxed{Resposta: log_{x}16=-2= \frac{1}{4} }](https://tex.z-dn.net/?f=log_%7Bx%7D16%3D-2%5C%5C%5C%5C%5C%5C%0A%28x%29%5E%7B-2%7D%3D16%5C%5C%5C%5C%5C%0A+%28%5Cfrac%7B1%7D%7B+x%5E%7B2%7D+%7D%29%3D16%5C%5C%5C%5C%5C%0A16+x%5E%7B2%7D+%3D1%5C%5C%5C%5C%5C%0A+x%5E%7B2%7D+%3D+%5Cfrac%7B1%7D%7B16%7D++%5C%5C%5C%5C%5C%5C%0Ax%3D+%5Csqrt%7B+%5Cfrac%7B1%7D%7B16%7D+%7D+%5C%5C%5C%5C%5C%5C%0Ax%3D+%5Cfrac%7B1%7D%7B4%7D%5C%5C%5C%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7BResposta%3A+log_%7Bx%7D16%3D-2%3D+%5Cfrac%7B1%7D%7B4%7D+%7D+ "log_{x}16=-2\\\\\\
(x)^{-2}=16\\\\\
(\frac{1}{ x^{2} })=16\\\\\
16 x^{2} =1\\\\\
x^{2} = \frac{1}{16} \\\\\\
x= \sqrt{ \frac{1}{16} } \\\\\\
x= \frac{1}{4}\\\\\\\\\
\boxed{Resposta: log_{x}16=-2= \frac{1}{4} }")
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Bons estudos!
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