Question

Resolva:

→ f(x) = - x² + 2x +3

Answer 1

zera o f(x)
Ai vc tira o delta
Delta = 4- 4(-3)
16
X= -2 +_ raiz de delta
______________
2a
-2+- 4
_____
-2
X1 = 3
X2 = -1
(se quiser passo a passo responde aqui q eu escrevo melhor)

Answer 2

Resposta:

$-x^{2}+2x+3=0\\ \\ Bhaskara:\\ x=\frac{-b+-\sqrt{b^{2}-4.a.c}}{2.a}\\ \\b^{2}-4.a.c=delta\\ \\ delta=2^{2}-4.(-1).3\\ \\ delta=4+12\\ \\ delta=16\\ \\ x=\frac{-b+-\sqrt{delta}}{-2}\\ \\ x=\frac{-2+-\sqrt{16}}{-2}\\ \\ x=\frac{-2+-4}{-2} \\ \\ x'=-\frac{-2+4}{-2}=\frac{2}{-2}=-1\\  \\ x''=\frac{-2-4}{-2}=\frac{-6}{-2} =3\\ \\ S~~(x'=-1;~~x''=3)$