Question

Resolva estes itens, quero com cálculos :D

Answer 1

Bom dia

a )

$log_{6} 22= log_{6}(2*11)=log_{6} 2 + log_{6} 11=0,37+1,34=1,71$

b)

$log_{6} \frac{2}{11} = log_{6}2- log_{6} 11=0,37-1,34=-0,97$

c)

$log_{6}5,5= log_{6} \frac{11}{2}= log_{6}11- log_{6}2=1,34-0,37=0,97$

d)

$log_{2}11= \frac{ log_{6}11 }{ log_{6}2 } = \frac{1,34}{0,37} =3,62$

e)

$log_{11}2= \frac{ log_{6}2 }{ log_{6}11 } = \frac{0,37}{1,34} =0,27$

f)

$log_{6}16 = log_{6} 2^{4} =4* log_{6} 2=4*0,34=1,36$