Question

resolva esta equacao com parentese 2(2x-4)=5-(x2+4)

Answer 1

2(2x-4)=5-(x2+4)
4x-8= 5-x^2-4
x^2+4x-8+4-5=0
x^2+4x-13+4=
x^2+4x-9=0
a=1
b=4
c= -9

∆= b^2-4.a.c
∆= 4^2-4.1.(-9)
∆= 16+36
∆= 52

x= -b+-✓52/2a
x= -4+-2✓13/2

x'= -4+2✓13/2=> -2-✓13

x"= -4-2✓13/2=> -2+✓13