Question

Resolva esses exercícios

1). (12/7- 2 1/7. 0,3333....) . [4/7 : (0,12 + 2/25)

2) 5 1/4 [4/9: (17/25 + 0,04)] + (3 1/2: 2,33....) ²

Me ajudem por favor :v

Answer 1

1)

$(\frac{12}{7}-2\frac{1}{7}.0,3333...).\frac{4}{7}\div (0,12+\frac{2}{25}=\\ \\ (\frac{12}{7}-\frac{15}{7}.\frac{1}{3}).\frac{4}{7}\div(\frac{12}{100}+\frac{8}{100})=\\ \\ (\frac{12}{7}-\frac{5}{7}) \div\frac{20}{100}=\\ \\ \frac{7}{7} \div \frac{1}{5}=1.\frac{5}{1}=5$

b)

$5 \frac{1}{4} [\frac{4}{9}\div (\frac{17}{25} + 0,04)] + (3 \frac{1}{2}\div 2,33....) ^2=\\ \\ \frac{21}{4}[\frac{4}{9}\div\frac{17}{25}+\frac{1}{25}]+(\frac{7}{2}\div\frac{7}{3})^2=\\ \\ \frac{21}{4}[\frac{4}{9}.\frac{25}{17}+\frac{1}{25}]+(\frac{7}{2}.\frac{3}{7})^2=\\ \\ \frac{21}{4}[\frac{100}{153}+\frac{1}{25}]+(\frac{3}{2})^2=\\ \\ \frac{21}{4}[\frac{2500+153}{3825}]+\frac{9}{4}=\\ \\ \frac{21}{4}[\frac{2653}{3825}]+\frac{9}{4}=\\ \\ \frac{55713}{15400}+\frac{9}{4}=\frac{90363}{15400}$