Question

resolva esse monômios
a) 2a²+3a²+4a²= h)15a³b²-5a³b²=
b) x²z³+10x²z³= i)16xb⁵-x6⁵=
c)8a⁵b⁶-2a⁵b⁶= j)3xyz+yz+12+yz=
d)7xy²-5xy²=
e)6a⁶b³+12a⁶b³=
f)8a²x³+2a²x³-5a²x³=
g)8xy³+2xy³=

Answer 1

a)
2a² + 3a² + 4a² = 9a²
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b)
x²z³+10x²z³= 11x²z³
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c)
8a⁵b⁶ - 2a⁵b⁶ = 6a⁵b⁶
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d)
7xy² - 5xy² = 2xy²
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e)
6a⁶b³ + 12a⁶b³ = 18a⁶b³
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f)
8a²x³ + 2a²x³ - 5a²x³ = 5a²b³
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g)
8xy³ + 2xy³ = 10xy³ 
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h)
= 15a³b² - 5a³b²
=10a³b²
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i)
= 16xb⁵ - xb⁵
= 15xb⁵

ou  (se for: 16xb⁵ - 6xb⁵)

16xb⁵ - 6xb⁵ = 10xb⁵
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j)
= 3xyz+yz+12+yz
= 3xyz + 2yz + 12