Question

resolva essa equçao do 2grau na forma de baskara:X² -5X +6=0

Answer 1

x² - 5x + 6 = 0

a = 1, b = - 5, c = 6

$\Delta=b^2-4a.c\\ \Delta=(-5)^2-4.1.6\\ \Delta=25-24\\ \Delta=1$

$x= \dfrac{-b \pm \sqrt{\Delta} }{2a}$

$x= \dfrac{5 \pm 1}{2} \\\\\\x'=3\\x''=2$

Forte abraço!

Answer 2

Olá!!!

x² - 5x + 6 = 0

a = 1 , b = - 5 , c = 6

∆ = b² - 4ac
∆ = ( - 5 )² - 4 • 1 • 6
∆ = 25 - 24
∆ = 1

x = - b ± √∆ / 2a
x = - ( - 5 ) ± √1 / 2 • 1
x = 5 ± 1 / 2
x' = 5 + 1 / 2 = 6 / 2 = 3
x'' = 5 - 1 / 2 = 4 / 2 = 2

S = { 2 , 3 }

Espero ter ajudado...