Question

resolva equações abaixo

a) 4*⁺² =256

b) 3*⁻⁵=27¹⁻*

c) 5²*⁻¹=1

Answer 1

a) $4^{x+2} =256$

$4^{x+2} =4^4$

Cancelando as bases:

$\not{4}^{x+2} =\not{4}^4$

x + 2 = 4
x = 4 - 2
x = 2



b) $3^{x+5}=27^{1-x}$

$3^{x+5}=(3^3)^{1-x}$

$3^{x+5}=3^{3-3x}$

Cancelando as bases:

$\not{3}^{x+5}=\not{3}^{3-3x}$

x + 5 = 3 - 3x
x + 3x = 3 - 5
4x = -2
x = -2/4
x = -1/2



c) $5^{2x-1}=1$

$5^{2x-1}=5^0$

Cancelando as bases:

$\not{5}^{2x-1}=\not{5}^0$

2x - 1 = 0
2x = 1
x = 1/2