Question

Resolva Equação do 2 grau, usando a formula de Báskara questão ײ -10×+9=0

Answer 1

Resposta:

Explicação passo-a-passo:

$\displaystyle Aplicando~a~f\acute{o}rmula~de~Bhaskara~para~x^{2}-10x+9=0~~e~comparando~com~(a)x^{2}+(b)x+(c)=0,~determinamos~os~coeficientes:~\\a=1{;}~b=-10~e~c=9\\\\C\acute{a}lculo~do~discriminante~(\Delta):&\\&~\Delta=(b)^{2}-4(a)(c)=(-10)^{2}-4(1)(9)=100-(36)=64\\\\C\acute{a}lculo~das~raizes:&\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(-10)-\sqrt{64}}{2(1)}=\frac{10-8}{2}=\frac{2}{2}=1\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(-10)+\sqrt{64}}{2(1)}=\frac{10+8}{2}=\frac{18}{2}=9\\\\S=\{1,~9\}$