Question

Resolva em R x^2-4x+1=0

Answer 1

∆=b^2-4ac
∆=(-4)^2-4.1.1
∆= 16 - 4
∆=12


x= -b + √∆ / 2a
x= - (-4) +√12 / 2.1
x= 4 + √12 / 2
(simplificando a raiz √12= √4.3= √2^2. 3= 2√3)
x= 4 + 2√3 / 2
x= 2+√3

x'= -b - √∆ / 2a
x= - (-4) -√12 / 2.1
x= 4 - √12 / 2
x= 4 - 2√3 / 2
x= 2-√3