Question

resolva em R as inequacoes+(x2-1)(x2+x+1)<0

Answer 1

Resposta:

x ∈ ⟨-1,1⟩

Explicação passo-a-passo:

+(x² -1)(x²+x+1)<0

↓

{x² -1<0

{x²+x+1>0

{x² -1>0

{x²+x+1<0

↓

{x ∈ ⟨-1,1⟩

{x ∈ ℝ

{x ∈ ⟨-∞,-1⟩ ∪ ⟨1,+∞⟩

{x ∈ ∅

↓

x ∈ ⟨-1,1⟩

x ∈ ∅

↓

x ∈ ⟨-1,1⟩