Question

Resolva ,em R as equações :

a ) (2x2 - 2x + 5) . (2x2 - 5x + 2) = 0

b ) (2x - 1) . (2x2 - 5x + 10) = (2x - 1) . (x2 + x + 1)

Answer 1

a)  (2x² - 2x + 5) . (2x² - 5x + 2) = 0
(4x -2x +5) (2x -5x +2) = 0
(2x +5) ( -3x +2) = 0
-6x² +4x -15x + 10 = 0  
-6x² -11x +10 = 0      (multiplica por -1)
6x² +11x -10 = 0

$\frac{-b +- \sqrt{b^{2} -4ac }}{2a}$

$\frac{-11 +- \sqrt{361}}{12}$ [/tex]
$\frac{-11 +- 19}{12}$

X'= $\frac{-11+19}{12}$ =0,666666666...
X'' = $\frac{-30}{12}$ =2,5

b)(2x - 1) . (2x² - 5x + 10) = (2x - 1) . (x² + x + 1)
(2x-1) . (-1x +10) = (2x-1) . (x²+x+1)
Cortando 2x -1 
-1x +10 = +x² +x +1
x² +2x -9

$\frac{-b +- \sqrt{b^{2} -4ac }}{2a}$
$\frac{-2 +- \sqrt{144}}{2}$

X'= $\frac{-2 +144}{2}$ = $\frac{142}{2}$ =71
X''= $\frac{-2 -144}{2}$ = $\frac{-146}{2}$ = -73

Espero ter ajudado ♡

Answer 2

Resposta:

oi

Explicação passo-a-passo: