Question

Resolva, em R, a equação (∛4)× = 32 e determine o seu conjunto solução

Answer 1

Resposta:

S={15/2}

Explicação passo-a-passo:

$\displaystyle\\(\sqrt[3]{4} )^{x}=32\\\\32|2\\16|2\\8|2\\4|2\\2|2\\1/2.2.2.2.2=2^{5}=32\\\\(\sqrt[3]{4})^{x}=32\\\\(\sqrt[3]{2^{2}})^{x}=2^{5}\\\\(2^{\frac{2}{3}})^{x}=2^{5}\\\\2^{\frac{2x}{3}}=2^{5}\\\\\frac{2x}{3}}=5\\\\2x=15\\\\x=\frac{15}{2}$