Question

Resolva com simplificação: a)
$\frac{ {x}^{2} - 5x + 6}{ {x}^{2} - 6x + 9 } =$B)
$\frac{xa + xb}{xa + xb - ya - yb} =$


Determine o valor de X: a)
$\frac{4x + 1}{2} + \frac{x + 3} {4} = \frac{3 x + 1}{4}$
Me Ajudem Pfvr

Answer 1

$A) \\ \\ \frac{x^2-5x+6}{x^2-6x+9} = \\ \\ fatorando \\ \\ \frac{(x-3)(x-2)}{(x-3)^2} = \frac{x-2}{x-3}$ 

$B) \\ \frac{xa+xb}{xa+xb-ya-yb} = \\ \\ \frac{x(a+b)}{x(a+b)-y(a+b)} = \\ \\ \frac{x(a+b)}{(x-y)(a+b)} = \\ \\ \frac{x}{x-y}$ 
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determine o valor de y

$\frac{4x+1}{2} + \frac{x+3}{4} = \frac{3x+1}{4} \\ \\ mmc(2,4)=4 \\ \\ 2(4x+1)+(x+3)=3x+1 \\ \\ 8x+2+x+3=3x+1 \\ \\ 8x+x-3x=1-2-3 \\ \\ 9x-3x=1-5 \\ \\ 6x=-4 \\ \\ x=- \frac{6}{4} ~~~~simplificando~~- \frac{6:2}{4:2} =- \frac{3}{2} \\ \\ x=- \frac{3}{2}$