Question

resolva com fórmula de Bhaskara X elevado ao quadrado mais 12x - 12 = 1

Answer 1

vamos lá...

x²+12x-12=1

x²+12x-12-1=0

x²+12x-13=0

a=1
b=12
c=-13

Δ=b²-4ac
Δ=12²-4(1)(-13)
Δ=144+52
Δ=196

$x= \frac{-b\pm \sqrt{\triangle} }{2a} = \frac{-12\pm \sqrt{196} }{2} =~~ \frac{-12\pm14}{2} \\ \\ x'= \frac{-12+14}{2} = \frac{2}{2} =1 \\ \\ x"= \frac{-12-14}{2} =- \frac{26}{2} =-13$