Question

Resolva cada equação:(3y+2).(y-1)=y.(y+2)

Answer 1

(3y + 2).(y - 1) = y. (y + 2)

3y² - 3y + 2y - 2 = y² + 2y
3y² - y² - y - 2y - 2
2y² - 3y - 2 = 0


delta = (-3)² - 4.2.(-2)
delta = 9 + 16
delta = 25


x = -(-3)² ± √25/2.2

x = 3 ± 5/4

x = 3 + 5/4 = 8/4 = 2

x = 3 - 5/4 = -2/4 = -1/2


s={ 2, -1/2 }




☆Espero ter ajudado!

Answer 2

(3y+2).(y-1)=y(y+2)
3y^2-3y+2y-2=y^2+2y
3y^2-y-2=y^2+2y
3y^2-y^2-y-2y-2=0
2y^2-3y-2=0
FORMULA BASKARA
a=2. b=-3. c=-2
delta=b^2-4ac
delta=(-3)^2-4(2)(-2)
delta=9-8(-2)
délta=9+16
delta=25
x=-b+,-\/delta/2a
x=-(-3)+,-\/25/2(2)
x=3+,- 5/4
x1=3+5/4》x1=8/4》x1=
x2=3-5/4》x2=-2/4(÷2)》x2=-1/2