Question

Resolva através da fórmula de bhaskara a seguinte função x²-10x+25=0

Answer 1

Olá!

Considerando a fórmula,

$\fbox{ \displaystyle x=\dfrac{-b\pm\sqrt{\Delta}}{2a} }$
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Resolução,

$\mathsf{x^2 - 10x + 25 = 0}$

$\mathsf{\Delta = b^2 - 4ac}$

$\mathsf{\Delta = 100 - 100}$

$\mathsf{\Delta = 0}$

$\mathsf{x=\dfrac{-b\pm\sqrt{\Delta}}{2a}}$

$\mathsf{x=\dfrac{10}{2}}$

$\boxed{\mathsf{x = 5}}$

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Abraços!