Question

resolva as sequintes equacoes, sendo U=R: 9x2=16​

Answer 1

Resposta:

OLÁ

VAMOS A SUA PERGUNTA:⇒⇒

$\sf 9x^2=16$

$\sf x^2=\dfrac{16}{9}$

$\sf x^2-\dfrac{16}{9} =0$

$\sf x=\dfrac{0\pm\sqrt{0^2-4\left(-\dfrac{16}{9}\right) } }{2}$

$\sf x=\dfrac{0\pm\sqrt{-4\left(-\dfrac{16}{9}\right) } }{2}$

$\sf x=\dfrac{0\pm\sqrt{\dfrac{64}{9} } }{2}$

$\sf x=\dfrac{0\pm\dfrac{8}{3 } }{2}$

$\sf \red{x=\dfrac{4}{3}=1\dfrac{1}{3} \approx 1.333333333}$

$\sf \blue{x=-\dfrac{4}{3}=-1\dfrac{1}{3} \approx -1.333333333}$

$\boxed{\bold{\displaystyle{\clubsuit\ \spadesuit\ \maltese\ \sf \red{x=\dfrac{4}{3}=1\dfrac{1}{3} \approx 1.333333333} }}}\ \checkmark \\\boxed{\bold{\displaystyle{\clubsuit\ \spadesuit\ \maltese\ \sf \blue{x=-\dfrac{4}{3}=-1\dfrac{1}{3} \approx -1.333333333}}}}\ \checkmark$←←⇵⇵↑↑ RESPOSTA.

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