Question

resolva as seguintes proporções:






S.O.S​

Answer 1

Resposta:

a)

x/5=21/35

x= 21.5/35.1

x= 105/35

x= 3

b) 10/7=50/x

x.10/7=50

10x/7=50

10x=50.7

x=350/10

x=35

c)1/7=(x-6)/49

49/7=x-6

7+6=x

13=x

d) (5x+3)/10=-21/30

5x+3=-210/30

5x+3=-7

5x=-10

x=-10/5=-2

e)5/(x+4)=30/54

5=(30x+120)/54

270=30x+120

150=30x

x=150/30=5

f)0,9/x=-18/27

(0,9.27)/x=-18

-24,3=-18x

-24,3/-18=x

x= 1,35

Answer 2

Resposta:

a) 35x = 21*5  

   x= 105/35  

   x= 3

b) 10x = 350    

   x = 350/10

   x = 35

c) 7 (x - 6) = 49

   7x - 42 = 49

   x = (49 + 42) / 7

    x = 13

d) 30 (5x + 30) = 10 (-21)

   150x + 90 = - 210

   150x = -210-90

   x = -300/150

   x = -2

e) 30 (x + 4) = 5 (54)

    30x + 120 = 270

     30x = 270 - 120

      x = 150 / 30

      x = 5

f) 27 ( 9/10 ) = - 18x

  243 / 10 = -18 x

  243 / 10 / -18 = x

  x = 243 / 10 * 1 / -18

  x = 243 / - 180  ( Dividir numerador e denominador por 9)

  x = 27 / -20

   x = - 27 / 20

g) (7x + 5) (3 / 4) = 8x

   (21x + 15) / 4 = 8x

   21x + 15 = 8x * 4

   21x + 15 = 32x

    32x - 21x = 15

    11x = 15

     x  = 15 / 11    

   

Explicação passo a passo:

Passo 1 - Multiplicar cruzado

Passo 2 - Isolar o x