resolva as seguintes proporções:
1/7=x-6/49
10/7=50/x
5x+3/10 =-21/30
7x+5/4 = 2x/3/4
Soluções para a tarefa
Respondido por
11
x=15/49
x=35
x=11/5 ou 2,2
x=-3
x=35
x=11/5 ou 2,2
x=-3
Respondido por
49
1/7=x-6/49
(x-6).7 = 1.49
7x -42 = 49
7x = 49+42
7x= 91
x= 91/7
x= 13
10/7=50/x
10.x = 50.7
10x = 350
x= 350/10
x= 35
5x+3/10 =-21/30
30.(5x +3) = 10.(-21)
150x +90 = - 210
150x = - 210-90
150x = -300
x= -300/150
x= -2
7x+5/4 = 2x/3/4
7x +5.(3/4) = 4.2x
(21x +15)/4 = 8x
8x .4 = 21x +15
32x = 21x +15mmm
32x -21x = 15
11x = 15
x = 15/11
(x-6).7 = 1.49
7x -42 = 49
7x = 49+42
7x= 91
x= 91/7
x= 13
10/7=50/x
10.x = 50.7
10x = 350
x= 350/10
x= 35
5x+3/10 =-21/30
30.(5x +3) = 10.(-21)
150x +90 = - 210
150x = - 210-90
150x = -300
x= -300/150
x= -2
7x+5/4 = 2x/3/4
7x +5.(3/4) = 4.2x
(21x +15)/4 = 8x
8x .4 = 21x +15
32x = 21x +15mmm
32x -21x = 15
11x = 15
x = 15/11
Perguntas interessantes