Question

Resolva as seguintes equações, sendo U=Q:

Answer 1

Explicação passo-a-passo:

a)

$\sf \dfrac{x}{2}+\dfrac{x}{3}=\dfrac{x+7}{3}$

$\sf 3x+2x=2\cdot(x+7)$

$\sf 5x=2x+14$

$\sf 5x-2x=14$

$\sf 3x=14$

$\sf \red{x=\dfrac{14}{3}}$

b)

$\sf \dfrac{x+2}{6}+\dfrac{x+1}{4}=6$

$\sf 2\cdot(x+2)+3\cdot(x+1)=12\cdot6$

$\sf 2x+4+3x+3=72$

$\sf 5x+7=72$

$\sf 5x=72-7$

$\sf 5x=65$

$\sf x=\dfrac{65}{5}$

$\sf \red{x=13}$

c)

$\sf \dfrac{x-2}{3}-\dfrac{x+1}{4}=4$

$\sf 4\cdot(x-2)-3\cdot(x+1)=12\cdot4$

$\sf 4x-8-3x-3=48$

$\sf x-11=48$

$\sf x=48+11$

$\sf \red{x=59}$

d)

$\sf \dfrac{x-1}{2}+\dfrac{x-2}{3}=\dfrac{x-3}{4}$

$\sf 6\cdot(x-1)+4\cdot(x-2)=3\cdot(x-3)$

$\sf 6x-6+4x-8=3x-9$

$\sf 6x+4x-3x=-9+8+6$

$\sf 7x=5$

$\sf \red{x=\dfrac{5}{7}}$