Resolva as seguintes equações no método completando quadrados
A) 10x² + 7x + 1 = 0
B) 3x² - 2x - 1 = 0
C) x² + 3x - 10 = 0
Soluções para a tarefa
A)
10x² + 7x + 1 = 0
x² + 7x/10 = -1/10
x² + 7x/10 + 49/400 = 9/400
(x + 7/20)² = 9/400
x + 7/20 = 3/20
x1 = -4/20 = -1/5
x + 7/20 = - 3/20
x2 = -10/20 = -1/2
B)
3x² - 2x - 1 = 0
x² - 2x/3 = 1/3
x² - 2x/3 + 1/9 = 4/9
(x - 1/3)² = 4/9
x - 1/3 = 2/3
x1 = 1/3 + 2/3 = 1
x - 1 = - 2/3
x2 = 1/3 - 2/3 = -1/3
C)
x² + 3x - 10 = 0
x² + 3x = 10
x² + 3x + 9/4 = 10 + 9/4
(x + 3/2)² = 49/4
x + 3/2 = 7/2
x1 = 7/2 - 3/2 = 4/2 = 2
x + 3/2 = -7/2
x2 = -7/2 - 3/2 = -10/2 = -5
Oi...
Resolução:
a)
10x² + 7x + 1 = 0
x² + 7x/10 = - 1/10
x² + 7x/10 + 49/400 = 9/400
(x + 7/20)² = 9/400
x + 7/20 = 3/20
x = 3/20 – 7/20
x’ = - 4/20 : 2
x’ = - 1/5
x + 7/20 = - 3/20
x = - 3/20 – 7/20
x” = - 10/20 : 10
x” = - 1/2
b)
3x² - 2x - 1 = 0
x² - 2x/3 = 1/3
x² - 2x/3 + 1/9 = 4/9
(x - 1/3)² = 4/9
x - 1/3 = 2/3
x’ = 1/3 + 2/3 = 1
x - 1 = - 2/3
x” = 1/3 - 2/3
x” = -1/3
c)
x² + 3x - 10 = 0
x² + 3x = 10
x² + 3x + 9/4 = 10 + 9/4
(x + 3/2)² = 49/4
x + 3/2 = 7/2
x1 = 7/2 - 3/2
x’ = 4/2
x’ = 2
x + 3/2 = - 7/2
x” = - 7/2 - 3/2
x” = -10/2
x” = - 5
Espero ter ajudado.
A)
10x² + 7x + 1 = 0
x² + 7x/10 = -1/10
x² + 7x/10 + 49/400 = 9/400
(x + 7/20)² = 9/400
x + 7/20 = 3/20
x1 = -4/20 = -1/5
x + 7/20 = - 3/20
x2 = -10/20 = -1/2
B)
3x² - 2x - 1 = 0
x² - 2x/3 = 1/3
x² - 2x/3 + 1/9 = 4/9
(x - 1/3)² = 4/9
x - 1/3 = 2/3
x1 = 1/3 + 2/3 = 1
x - 1 = - 2/3
x2 = 1/3 - 2/3 = -1/3
C)
x² + 3x - 10 = 0
x² + 3x = 10
x² + 3x + 9/4 = 10 + 9/4
(x + 3/2)² = 49/4
x + 3/2 = 7/2
x1 = 7/2 - 3/2 = 4/2 = 2
x + 3/2 = -7/2
x2 = -7/2 - 3/2 = -10/2 = -5