Question

Resolva as seguintes equações exponenciais: a)4^×=32= b)(1/2)^×=1/2 c)8^×^+1=128^×-3= G)2^×+1=1 H)27^×+1=9= I) (1/4)^-×+2=32=

Answer 1

Resposta:

a)4^×=32   ==>2^(2x)=2^5  ==>2x=5 ==>x=5/2

b)(1/2)^×=1/2 ==>x=1

c)8^(×+1)=128^(×-3)= 2^(3x+3)=2^(7x-21)  

3x+3=7x-21

4x=24

x=6

G)2^(×+1)=1=2^0   ==> x+1=0  ==>x=-1

H)27^(×+1)=9==>3^(3x+3)=3²  ==>3x+3=2 ==>x=-1/3

I) (1/4)^(-×+2)=32==>2^(2x-4)=2^5

2x-4=5

x=9/2